Tabla de derivadas
Publicado por Profesor - 13/12/09 a las 12:12:48 amHoy os traemos una tabla de derivadas
Tabla de Derivadas e Integrales
Publicado por Profesor - 28/04/08 a las 04:04:50 pmTabla de Derivadas e Integrales
|
Derivada |
Integral |
|
|
y = c |
y’ = 0 |
c.x |
|
y = c.x |
y’ = c |
c.x2/2 |
|
y = xn |
y’ = n.xn-1 |
xn+1/n+1 |
|
y = x-n |
y’ = -1/(n.xn-1) |
x-n+1/-n+1 |
|
y = x½ |
y’ = 1/(2.x½) |
2.x3/2/3 |
|
y = xa/b |
y’ = a.x(a/b)-1/b |
x(a/b)+1/[(a/b)+1] |
|
y = 1/x |
y’ = -1/x2 |
ln x |
|
y = sen x |
y’ = cos x |
-cos x |
|
y = cos x |
y’ = -sen x |
sen x |
|
y = tg x |
y’ = 1/cos2x |
-ln cos x |
|
y = cotg x |
y’ = -1/sen2x |
ln sen x |
|
y = sec x |
y’ = sen x/cos2x |
ln (tg ½.x) |
|
y = cosec x |
y’ = -cos x/sen2x |
ln [cos x/(1 - sen x)] |
|
y = arcsen x |
y’ = 1/(1 – x2)½ |
x.arcsen x + (1 – x2)½ |
|
y = arccos x |
y’ = -1/(1 – x2)½ |
x.arccos x – (1 – x2)½ |
|
y = arctg x |
y’ = 1/(1 + x2) |
x.arctg x – ½ln (1 + x2) |
|
y = arccotg x |
y’ = -1/(1 + x2) |
x.arccotg x + ½ln (1 + x2) |
|
y = arcsec x |
y’ = 1/[x.(x2 -1)½] |
1 |
|
y = arccosec x |
y’ = -1/[x.(x2 – 1)½] |
2 |
|
y = senh x |
y’ = cosh x |
cosh x |
|
y = cosh x |
y’ = senh x |
senh x |
|
y = tgh x |
y’ = sech2x |
ln cosh x |
|
y = cotgh x |
y’ = -cosech2x |
ln senh x |
|
y = sech x |
y’ = -sech x.tgh x |
3 |
|
y = cosech x |
y’ = -cosech x.cotgh x |
4 |
|
y = ln x |
y’ = 1/x |
x.(ln x – 1) |
|
y = logax |
y’ = 1/x.ln a |
x.( logax – 1/ln a) |
|
y = ex |
y’ = ex |
ex |
|
y = ax |
y’ = ax.ln a |
ax/ln a |
|
y = xx |
y’ = xx.(ln x + 1) |
5 |
|
y = eu |
y’ = eu.u’ |
6 |
|
y = u.v |
y’ = u’.v + v’.u |
òu.dv + òv.du |
|
y = u/v |
y’ = (u’.v – v’.u)/v2 |
7 |
|
y = uv |
y’ = uv.(v’.lnu + v.u’/u) |
8 |
|
y = lnuv |
y’ = (v’.u.lnu – u’.v.lnv)/v.u.ln2u |
9 |
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